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0.1x^2=1.5
We move all terms to the left:
0.1x^2-(1.5)=0
We add all the numbers together, and all the variables
0.1x^2-1.5=0
a = 0.1; b = 0; c = -1.5;
Δ = b2-4ac
Δ = 02-4·0.1·(-1.5)
Δ = 0.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{0.6}}{2*0.1}=\frac{0-\sqrt{0.6}}{0.2} =-\frac{\sqrt{}}{0.2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{0.6}}{2*0.1}=\frac{0+\sqrt{0.6}}{0.2} =\frac{\sqrt{}}{0.2} $
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